# Floor, Ceil and Rint – HackerRank Solution Python

Floor, Ceil and Rint

floor
The tool floor returns the floor of the input element-wise.
The floor of x is the largest integer i where i<=x .

```import numpy

my_array = numpy.array([1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7, 8.8, 9.9])
print numpy.floor(my_array)         #[ 1.  2.  3.  4.  5.  6.  7.  8.  9.]
```

ceil
The tool ceil returns the ceiling of the input element-wise.
The ceiling of x is the smallest integer i where i>=x .

```import numpy

my_array = numpy.array([1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7, 8.8, 9.9])
print numpy.ceil(my_array)          #[  2.   3.   4.   5.   6.   7.   8.   9.  10.]
```

rint
The rint tool rounds to the nearest integer of input element-wise.

```import numpy

my_array = numpy.array([1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7, 8.8, 9.9])
print numpy.rint(my_array)          #[  1.   2.   3.   4.   6.   7.   8.   9.  10.]
```

You are given a 1-D array, A. Your task is to print the floor , ceil and rint of all the elements of A.

Note
In order to get the correct output format, add the line numpy.set_printoptions(legacy=’1.23′) below the numpy import.

Input Format

A single line of input containing the space separated elements of array A.

Output Format

On the first line, print the floor of A.
On the second line, print the ceil of A.
On the third line, print the rint of A.

Sample Input

```1.1 2.2 3.3 4.4 5.5 6.6 7.7 8.8 9.9
```

Sample Output

```[ 1.  2.  3.  4.  5.  6.  7.  8.  9.]
[  2.   3.   4.   5.   6.   7.   8.   9.  10.]
[  1.   2.   3.   4.   6.   7.   8.   9.  10.]```

Code:

```import numpy
numpy.set_printoptions(legacy="1.13")

A = list(map(float,input().strip().split()))

my_array = numpy.array(A)
print(numpy.floor(my_array))
print(numpy.ceil(my_array))
print(numpy.rint(my_array))```

Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.