itertools.product() Hackerrank Solution Python

Problem: itertools.product() Hackerrank Solution Python

itertools.product()

This tool computes the cartesian product of input iterables.
It is equivalent to nested for-loops.
For example, product(A, B) returns the same as ((x,y) for x in A for y in B).

_{Sample Code}

>>> from itertools import product
>>>
>>> print list(product([1,2,3],repeat = 2))
[(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)]
>>>
>>> print list(product([1,2,3],[3,4]))
[(1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (3, 4)]
>>>
>>> A = [[1,2,3],[3,4,5]]
>>> print list(product(*A))
[(1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 3), (3, 4), (3, 5)]
>>>
>>> B = [[1,2,3],[3,4,5],[7,8]]
>>> print list(product(*B))
[(1, 3, 7), (1, 3, 8), (1, 4, 7), (1, 4, 8), (1, 5, 7), (1, 5, 8), (2, 3, 7), (2, 3, 8), (2, 4, 7), (2, 4, 8), (2, 5, 7), (2, 5, 8), (3, 3, 7), (3, 3, 8), (3, 4, 7), (3, 4, 8), (3, 5, 7), (3, 5, 8)]

Task

You are given a two lists A and B. Your task is to compute their cartesian product AXB.

_Example

A = [1, 2]
B = [3, 4]

AxB = [(1, 3), (1, 4), (2, 3), (2, 4)]

Note: A and B are sorted lists, and the cartesian product’s tuples should be output in sorted order.

Input Format

The first line contains the space separated elements of list A.
The second line contains the space separated elements of list B.

Both lists have no duplicate integer elements.

Constraints

0<A<30

0<B<30

Output Format

Output the space separated tuples of the cartesian product.

Sample Input

 1 2
 3 4

Sample Output

 (1, 3) (1, 4) (2, 3) (2, 4)

Code:

#
a=[]
b=[]
a=[int(item) for item in input("").split()]
b=[int(item) for item in input("").split()]

for i in range(len(a)):
    
    for j in range(len(b)):
        print("("+str(a[i])+", "+str(b[j])+")",end=" ")

Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.