Java Anagrams Hackerrank Solution

Two strings, a and b, are called anagrams if they contain all the same characters in the same frequencies. For this challenge, the test is not case-sensitive. For example, the anagrams of CAT are CAT, ACT, tac, TCA, aTC, and CtA.

Function Description

Complete the isAnagram function in the editor.

isAnagram has the following parameters:

• string a: the first string
• string b: the second string

Returns

• boolean: If a and b are case-insensitive anagrams, return true. Otherwise, return false.

Input Format

The first line contains a string .
The second line contains a string .

Constraints

• 1<=length(a),length(b)<=50
• Strings  and  consist of English alphabetic characters.
• The comparison should NOT be case sensitive.

Sample Input 0

anagram
margana

Sample Output 0

Anagrams

Explanation 0

Character	Frequency: anagram	Frequency: margana
A or a	3	3
G or g	1	1
N or n	1	1
M or m	1	1
R or r	1	1

The two strings contain all the same letters in the same frequencies, so we print “Anagrams”.

Sample Input 1

anagramm
marganaa

Sample Output 1

Not Anagrams

Explanation 1

Character	Frequency: anagramm	Frequency: marganaa
A or a	3	4
G or g	1	1
N or n	1	1
M or m	2	1
R or r	1	1

The two strings don’t contain the same number of a‘s and m‘s, so we print “Not Anagrams”.

Sample Input 2

Hello
hello

Sample Output 2

Anagrams

Explanation 2

Character	Frequency: Hello	Frequency: hello
E or e	1	1
H or h	1	1
L or l	2	2
O or o	1	1

The two strings contain all the same letters in the same frequencies, so we print “Anagrams”.

Code Solution:

//Java Anagrams Hackerrank Solution

import java.util.Scanner;

public class Solution {

    

    static boolean isAnagram(String a, String b) {
        // Complete the function
        char aa[] = a.toLowerCase().toCharArray();
        char bb[] = b.toLowerCase().toCharArray();
        if(a.length() != b.length()){
            return false;
        }else{
            java.util.Arrays.sort(aa);
            java.util.Arrays.sort(bb);
            return java.util.Arrays.equals(aa, bb);
        }

    }
    public static void main(String[] args) {
    
        Scanner scan = new Scanner(System.in);
        String a = scan.next();
        String b = scan.next();
        scan.close();
        boolean ret = isAnagram(a, b);
        System.out.println( (ret) ? "Anagrams" : "Not Anagrams" );
    }
}

//Java Anagrams Hackerrank Solution

Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.