Java Datatypes Hackerrank Soluiton

Java Datatypes Hackerrank Soluiton
Java Datatypes Hackerrank Soluiton

Java Datatypes Hackerrank Soluiton

Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we’ll work with the primitives used to hold integer values (byte, short, int, and long):

  • byte is an 8-bit signed integer.
  • short is a 16-bit signed integer.
  • An int is a 32-bit signed integer.
  • long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input.

To get you started, a portion of the solution is provided for you in the editor.


Input Format

The first line contains an integer, T, denoting the number of test cases.
Each test case, T, is comprised of a single line with an integer, n, which can be arbitrarily large or small.

Output Format

For each input variable n and appropriate primitive dataType, you must determine if the given primitives are capable of storing it. If yes, then print:

n can be fitted in:
* dataType

If there is more than one appropriate data type, print each one on its own line and order them by size (i.e.: byte<short<int<long).

If the number cannot be stored in one of the four aforementioned primitives, print the line:

n can't be fitted anywhere.

Sample Input


Sample Output

-150 can be fitted in:
* short
* int
* long
150000 can be fitted in:
* int
* long
1500000000 can be fitted in:
* int
* long
213333333333333333333333333333333333 can't be fitted anywhere.
-100000000000000 can be fitted in:
* long


 -150 can be stored in a short, an int, or a long.

2133333333333333333333333333333333333 is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.

Java Datatypes Hackerrank Soluiton Code solution :

// Java Datatypes Hackerrank Soluiton

import java.util.*;

class Solution{
    public static void main(String []argh)

        Scanner sc = new Scanner(;
        int t=sc.nextInt();

        for(int i=0;i<t;i++)

                long x=sc.nextLong();
                System.out.println(x+" can be fitted in:");
                if(x>=-128 && x<=127)System.out.println("* byte");
                if(x>=Short.MIN_VALUE && x<=Short.MAX_VALUE)System.out.println("* short");
                 if(x>=Integer.MIN_VALUE && x<=Integer.MAX_VALUE)System.out.println("* int");
                  if(x>=Long.MIN_VALUE && x<=Long.MAX_VALUE)
                  System.out.println("* long");
                  System.out.println(x+" can't be fitted anywhere.");
                //Complete the code
            catch(Exception e)
                System.out.println(" can't be fitted anywhere.");


// Java Datatypes Hackerrank Soluiton

Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.

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