Java Datatypes Hackerrank Soluiton

Java Datatypes Hackerrank Soluiton
Java Datatypes Hackerrank Soluiton

Java Datatypes Hackerrank Soluiton

Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we’ll work with the primitives used to hold integer values (byte, short, int, and long):

  • byte is an 8-bit signed integer.
  • short is a 16-bit signed integer.
  • An int is a 32-bit signed integer.
  • long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input.

To get you started, a portion of the solution is provided for you in the editor.

Reference: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

Input Format

The first line contains an integer, T, denoting the number of test cases.
Each test case, T, is comprised of a single line with an integer, n, which can be arbitrarily large or small.

Output Format

For each input variable n and appropriate primitive dataType, you must determine if the given primitives are capable of storing it. If yes, then print:

n can be fitted in:
* dataType

If there is more than one appropriate data type, print each one on its own line and order them by size (i.e.: byte<short<int<long).

If the number cannot be stored in one of the four aforementioned primitives, print the line:

n can't be fitted anywhere.

Sample Input

5
-150
150000
1500000000
213333333333333333333333333333333333
-100000000000000

Sample Output

-150 can be fitted in:
* short
* int
* long
150000 can be fitted in:
* int
* long
1500000000 can be fitted in:
* int
* long
213333333333333333333333333333333333 can't be fitted anywhere.
-100000000000000 can be fitted in:
* long

Explanation

 -150 can be stored in a short, an int, or a long.

2133333333333333333333333333333333333 is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.

Java Datatypes Hackerrank Soluiton Code solution :

 
// Java Datatypes Hackerrank Soluiton

import java.util.*;
import java.io.*;



class Solution{
    public static void main(String []argh)
    {



        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();

        for(int i=0;i<t;i++)
        {

            try
            {
                long x=sc.nextLong();
                System.out.println(x+" can be fitted in:");
                if(x>=-128 && x<=127)System.out.println("* byte");
                if(x>=Short.MIN_VALUE && x<=Short.MAX_VALUE)System.out.println("* short");
                 if(x>=Integer.MIN_VALUE && x<=Integer.MAX_VALUE)System.out.println("* int");
                  if(x>=Long.MIN_VALUE && x<=Long.MAX_VALUE)
                  System.out.println("* long");
                  else
                  System.out.println(x+" can't be fitted anywhere.");
                  
                //Complete the code
            }
            catch(Exception e)
            {
                System.out.println(sc.next()+" can't be fitted anywhere.");
            }

        }
    }
}



// Java Datatypes Hackerrank Soluiton

Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.

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