Java Exception Handling (Try-catch) Hackerrank Solution

Exception handling is the process of responding to the occurrence, during computation, of exceptions – anomalous or exceptional conditions requiring special processing – often changing the normal flow of program execution. (Wikipedia)

Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.

This problem will test your knowledge on try-catch block.

You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if y is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.

Sample Input 0:

10
3

Sample Output 0:

Sample Input 1:

10
Hello

Sample Output 1:

java.util.InputMismatchException

Sample Input 2:

10
0

Sample Output 2:

java.lang.ArithmeticException: / by zero

Sample Input 3:

23.323
0

Sample Output 3:

java.util.InputMismatchException

Code Solution:

//Java Exception Handling (Try-catch) Hackerrank Solution
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner sc = new Scanner(System.in);
        try {
      int x=sc.nextInt();
      int y=sc.nextInt();
      System.out.println(x/y);
    } 
    catch(InputMismatchException e){
        System.out.println("java.util.InputMismatchException");
    }
    catch (Exception e) {
      System.out.println(e);
    }   
    }
}
//Java Exception Handling (Try-catch) Hackerrank Solution

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