
In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Source: Wikipedia
Task
Given an integer, n, perform the following conditional actions:
- If is odd, print
Weird
- If is even and in the inclusive range of 2 to 5, print
Not Weird
- If is even and in the inclusive range of 6 to 20, print
Weird
- If is even and greater than 20, print
Not Weird
Complete the stub code provided in your editor to print whether or not n is weird.
Input Format
A single line containing a positive integer, n.
Constraints
- 1<=n<=100
Output Format
Print Weird
if the number is weird; otherwise, print Not Weird
.
Sample Input 0
3
Sample Output 0
Weird
Sample Input 1
24
Sample Output 1
Not Weird
Explanation
Sample Case 0: n=3
n is odd and odd numbers are weird, so we print Weird
.
Sample Case 1: n=24
n>20 and n is even, so it isn’t weird. Thus, we print Not Weird
.
Code Solution:
//Java If-Else hackerrank solution import java.io.*; import java.math.*; import java.security.*; import java.text.*; import java.util.*; import java.util.concurrent.*; import java.util.regex.*; public class Solution { private static final Scanner scanner = new Scanner(System.in); public static void main(String[] args) { int N = scanner.nextInt(); if(N%2!=0) System.out.println("Weird"); else if((N%2==0) && 2<= N & N<6) System.out.println("Not Weird"); else if((N%2==0) && 6<= N & N<22) System.out.println("Weird"); else System.out.println("Not Weird"); scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?"); scanner.close(); } } //Java If-Else hackerrank solution
Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.