Java Strings Introduction Hackerrank Solution

Java Strings Introduction Hackerrank Solution

This exercise is to test your understanding of Java Strings. A sample String declaration:

String myString = "Hello World!"

The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.

Given two strings of lowercase English letters, A and B, perform the following operations:

1. Sum the lengths of A and B.
2. Determine if A is lexicographically larger than  B(i.e.: does B come before A in the dictionary?).
3. Capitalize the first letter in A and B and print them on a single line, separated by a space.

Input Format

The first line contains a string A. The second line contains another string B. The strings are comprised of only lowercase English letters.

Output Format

There are three lines of output:
For the first line, sum the lengths of A and B.
For the second line, write Yes if  is lexicographically greater than  otherwise print No instead.
For the third line, capitalize the first letter in both A and  B and print them on a single line, separated by a space.

Sample Input 0

hello
java

Sample Output 0

9
No
Hello Java

Code: Solution:

// Java Strings Introduction Hackerrank Solution

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        
        Scanner sc=new Scanner(System.in);
        String A=sc.next();
        String B=sc.next();
        /* Enter your code here. Print output to STDOUT. */
        System.out.println(A.length()+B.length());
       int compare = A.compareTo(B);  

if (compare < 0) {  
    System.out.println("No");
}
else if(compare>0) {
    System.out.println("Yes");
}
else{
    System.out.println("No");
}
String C = A.substring(0, 1).toUpperCase() + A.substring(1);
String D = B.substring(0, 1).toUpperCase() + B.substring(1);
System.out.println(C+" "+D);

    }

}

//Java Strings Introduction Hackerrank Solution

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