Re.start() & Re.end() HackerRank Solution

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Re.start() & Re.end() HackerRank Solution
Re.start() & Re.end()

Re.start() & Re.end() HackerRank Solution Python

start() & end()

These expressions return the indices of the start and end of the substring matched by the group.

Code

>>> import re
>>> m = re.search(r'\d+','1234')
>>> m.end()
4
>>> m.start()
0

Task
You are given a string S.
Your task is to find the indices of the start and end of string k in S.

Input Format

The first line contains the string S.
The second line contains the string k.

Constraints

Output Format

Print the tuple in this format: (start _index, end _index).
If no match is found, print (-1, -1).

Sample Input

aaadaa
aa

Sample Output

(0, 1)  
(1, 2)
(4, 5)

Code:


import re
S=input()
k=input()
m=re.finditer(r'(?=(' + k + '))',S)

match=False
for i in m:
    match=True
    print((i.start(1),i.end(1)-1))
if match==False:
    print((-1,-1))

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