Given a list of rational numbers,find their product.
Concept
The reduce() function applies a function of two arguments cumulatively on a list of objects in succession from left to right to reduce it to one value. Say you have a list, say [1,2,3] and you have to find its sum.
>>> reduce(lambda x, y : x + y,[1,2,3]) 6
You can also define an initial value. If it is specified, the function will assume initial value as the value given, and then reduce. It is equivalent to adding the initial value at the beginning of the list. For example:
>>> reduce(lambda x, y : x + y, [1,2,3], -3) 3 >>> from fractions import gcd >>> reduce(gcd, [2,4,8], 3) 1
Input Format
First line contains n, the number of rational numbers.
The ith of next n lines contain two integers each, the numerator( Ni ) and denominator( Di ) of the ith rational number in the list.
Constraints
- 1<=n<=100
- 1<=Ni,Di<=10^9
Output Format
Print only one line containing the numerator and denominator of the product of the numbers in the list in its simplest form, i.e. numerator and denominator have no common divisor other than 1.
Sample Input 0
3 1 2 3 4 10 6
Sample Output 0
5 8
Explanation 0
Required product is 1/2*3/4*10/6=5/8
Code:
from __future__ import print_function
from fractions import Fraction
def product(fracs):
t = Fraction(reduce(lambda x,y:x*y,fracs))# complete this line with a reduce statement
return t.numerator, t.denominator
if __name__ == '__main__':
fracs = []
for _ in range(input()):
fracs.append(Fraction(*map(int, raw_input().split())))
result = product(fracs)
print(*result)
Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.
