Validating Email Addresses With a Filter Hackerrank Solution
You are given an integer N followed by N email addresses. Your task is to print a list containing only valid email addresses in lexicographical order.
Valid email addresses must follow these rules:
- It must have the username@websitename.extension format type.
- The username can only contain letters, digits, dashes and underscores .
[a-z],[A_Z],[0-9],[_-]
- The website name can only have letters and digits .
[a-z],[A_Z],[0-9]
- The extension can only contain letters .[a-z],[A-Z]
- The maximum length of the extension is 3.
Concept
A filter takes a function returning True or False and applies it to a sequence, returning a list of only those members of the sequence where the function returned True. A Lambda function can be used with filters.
Let’s say you have to make a list of the squares of integers from to (both included).
>> l = list(range(10)) >> l = list(map(lambda x:x*x, l))
Now, you only require those elements that are greater than 10 but less than 80.
>> l = list(filter(lambda x: x > 10 and x < 80, l))
Easy, isn’t it?
Example
Complete the function fun in the editor below.
fun has the following paramters:
- string s: the string to test
Returns
- boolean: whether the string is a valid email or not
Input Format
The first line of input is the integer N, the number of email addresses.
N lines follow, each containing a string.
Constraints
Each line is a non-empty string.
Sample Input
3 lara@hackerrank.com brian-23@hackerrank.com britts_54@hackerrank.com
Sample Output
['brian-23@hackerrank.com', 'britts_54@hackerrank.com', 'lara@hackerrank.com']
Code:
import re
def fun(s):
pt=re.compile("([a-zA-Z0-9_-]+)@([a-zA-Z0-9]+)\.([a-zA-z]{1,3})$")
return pt.match(s)
def filter_mail(emails):
return filter(fun, emails)
if __name__ == '__main__':
n = int(raw_input())
emails = []
for _ in range(n):
emails.append(raw_input())
filtered_emails = filter_mail(emails)
filtered_emails.sort()
print filtered_emails
Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.
