Validating Email Addresses With a Filter Hackerrank solution

Validating Email Addresses With a Filter Hackerrank Solution
Validating Email Addresses With a Filter

Validating Email Addresses With a Filter Hackerrank Solution

You are given an integer N followed by N email addresses. Your task is to print a list containing only valid email addresses in lexicographical order.

Valid email addresses must follow these rules:

  • It must have the username@websitename.extension format type.
  • The username can only contain letters, digits, dashes and underscores .


  • The website name can only have letters and digits .


  • The extension can only contain letters .[a-z],[A-Z]
  • The maximum length of the extension is 3.


filter takes a function returning True or False and applies it to a sequence, returning a list of only those members of the sequence where the function returned True. A Lambda function can be used with filters.

Let’s say you have to make a list of the squares of integers from  to  (both included).

>> l = list(range(10))
>> l = list(map(lambda x:x*x, l))

Now, you only require those elements that are greater than 10 but less than 80.

>> l = list(filter(lambda x: x > 10 and x < 80, l))

Easy, isn’t it?


Complete the function fun in the editor below.

fun has the following paramters:

  • string s: the string to test


  • boolean: whether the string is a valid email or not

Input Format

The first line of input is the integer N, the number of email addresses.
N lines follow, each containing a string.


Each line is a non-empty string.

Sample Input


Sample Output

['', '', '']


import re
def fun(s):
    return pt.match(s)

def filter_mail(emails):
    return filter(fun, emails)

if __name__ == '__main__':
    n = int(raw_input())
    emails = []
    for _ in range(n):

    filtered_emails = filter_mail(emails)
    print filtered_emails

Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.

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