Zipped! Hackerrank Solution Python
This function returns a list of tuples. The ith tuple contains the ith element from each of the argument sequences or iterables.
If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.
Sample Code
>>> print zip([1,2,3,4,5,6],'Hacker') [(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')] >>> >>> print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1]) [(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)] >>> >>> A = [1,2,3] >>> B = [6,5,4] >>> C = [7,8,9] >>> X = [A] + [B] + [C] >>> >>> print zip(*X) [(1, 6, 7), (2, 5, 8), (3, 4, 9)]
Task
The National University conducts an examination of N students in X subjects.
Your task is to compute the average scores of each student.
Average Score=Sum of scores obtained in all subjects by a student/Total number of subjects
The format for the general mark sheet is:
Student ID → ___1_____2_____3_____4_____5__
Subject 1 | 89 90 78 93 80
Subject 2 | 90 91 85 88 86
Subject 3 | 91 92 83 89 90.5
|______________________________
Average 90 91 82 90 85.5
Input Format
The first line contains N and X separated by a space.
The next X lines contains the space separated marks obtained by students in a particular subject.
Constraints
0<N<=100
0<=X<=100
Output Format
Print the averages of all students on separate lines.
The averages must be correct up to 1 decimal place.
Sample Input
5 3 89 90 78 93 80 90 91 85 88 86 91 92 83 89 90.5
Sample Output
90.0 91.0 82.0 90.0 85.5
Code:
N,S=map(int,input().split())
A=[]
for i in range(S):
a=list(map(float,input().split()))
A.append(a)
for i in zip(*A):
print(sum(i)/len(i))
Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.