## Zipped! Hackerrank Solution Python

This function returns a list of tuples. The i^{th} tuple contains the i^{th} element from each of the argument sequences or iterables.

If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.

_{Sample Code}

>>> print zip([1,2,3,4,5,6],'Hacker') [(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')] >>> >>> print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1]) [(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)] >>> >>> A = [1,2,3] >>> B = [6,5,4] >>> C = [7,8,9] >>> X = [A] + [B] + [C] >>> >>> print zip(*X) [(1, 6, 7), (2, 5, 8), (3, 4, 9)]

**Task**

The National University conducts an examination of N students in X subjects.

Your task is to compute the *average scores* of each student.

Average Score=Sum of scores obtained in all subjects by a student/Total number of subjects

The format for the general mark sheet is:

Student ID → ___1_____2_____3_____4_____5__ Subject 1 | 89 90 78 93 80 Subject 2 | 90 91 85 88 86 Subject 3 | 91 92 83 89 90.5 |______________________________ Average 90 91 82 90 85.5

**Input Format**

The first line contains N and X separated by a space.

The next X lines contains the space separated marks obtained by students in a particular subject.

**Constraints**

0<N<=100

0<=X<=100

**Output Format**

Print the averages of all students on separate lines.

The averages must be correct up to 1 decimal place.

**Sample Input**

5 3 89 90 78 93 80 90 91 85 88 86 91 92 83 89 90.5

**Sample Output**

90.0 91.0 82.0 90.0 85.5

Code:

N,S=map(int,input().split()) A=[] for i in range(S): a=list(map(float,input().split())) A.append(a) for i in zip(*A): print(sum(i)/len(i))

Disclaimer: This problem is originally created and published by HackerRank, we only provide solutions to this problem. Hence, doesn’t guarantee the truthfulness of the problem. This is only for information purposes.